Question

Factorise by splitting the middle term 3x²+14x-5​

Answer 1

Answer:

STEP1:Equation at the end of step 1

(3x2 - 14x) - 5

STEP2:Trying to factor by splitting the middle term

 2.1     Factoring  3x2-14x-5 

The first term is,  3x2  its coefficient is  3 .

The middle term is,  -14x  its coefficient is  -14 .

The last term, "the constant", is  -5 

Step-1 : Multiply the coefficient of the first term by the constant   3 • -5 = -15 

Step-2 : Find two factors of  -15  whose sum equals the coefficient of the middle term, which is   -14 .

     -15   +   1   =   -14   That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -15  and  1 

                     3x2 - 15x + 1x - 5

Step-4 : Add up the first 2 terms, pulling out like factors :

                    3x • (x-5)

              Add up the last 2 terms, pulling out common factors :

                     1 • (x-5)

Step-5 : Add up the four terms of step 4 :

                    (3x+1)  •  (x-5)

             Which is the desired factorization

Final result :

(x - 5) • (3x + 1)

Answer 2

Step-by-step explanation:

3x²+14x-5

3x²+(15-1)x-5

3x²+15x-1x-5

3x(x+5)-1(x+5)

(x+5)(3x-1)