Question

Factorise by splitting the middle term in( x square -10x+9)

Answer 1

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$\implies {x}^{2} - 10x + 9 \\ \\ = {x}^{2} - (9 + 1)x + 9 \\ \\ = {x}^{2} - 9x - x + 9 \\ \\ = {x}^{2} - x - 9x + 9 \\ \\ = x(x - 1) - 9(x - 1) \\ \\ = (x - 9)(x - 1)$

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Answer 2

Answer:

x= 9 or 1

Step-by-step explanation:

x²-10x+9=0

x²-9x-x+9=0

x(x-9)-1(x-9)=0

(x-9)(x-1)=0

x= 9 or 1