Math, asked by bhayNarasimhan321, 1 year ago

Factorise by splitting the middle term of 9(x-2y)^2 - 4(x-2y)-13

Answers

Answered by TPS
42
9(x-2y)^2 - 4(x-2y)-13
= 9(x-2y)^2 + 9(x-2y) - 13(x-2y)-13
= 9(x-2y) [ (x-2y) + 1 ] – 13 [ (x-2y) + 1 ]
= [ (x-2y) + 1 ] [ 9(x-2y) + 1 ]
= [ (x-2y) + 1 ] [ 9x - 18y + 1 ]
= (x-2y+1)(9x-18y+1)
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