Question

factorise by taking out Common Factor x(x+y)^3-3x^2y (x+y) ​

Answer 1

Step-by-step explanation:

Answer

Given : x(x+y)

3

−3x

2

y(x+y)

Taking x(x+y) as common in the given question,

we get, x(x+y)[(x+y)

2

−3xy]

We know that, (a+b)

2

=a

2

+b

2

+2ab

x(x+y)

3

−3x

2

y(x+y)=x(x+y)(x

2

+y

2

+2xy−3xy)

So we get,

x(x+y)

3

−3x

2

y(x+y)=x(x+y)(x

2

+y

2

−xy)