factorise by taking out the common factor : 2x(a-b)+3y(5a-5b)+4z(2b-2a)
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Answered by
182
Hi ,
2x( a - b ) + 3y( 5a - 5b ) + 4z ( 2b - 2a )
= 2x ( a - b ) + 3y × 5( a - b ) - 4z × 2 ( a - b )
= 2x( a - b ) + 15y( a - b ) - 8z ( a - b )
= ( a - b ) ( 2x + 15y - 8z )
I hope this helps you.
: )
2x( a - b ) + 3y( 5a - 5b ) + 4z ( 2b - 2a )
= 2x ( a - b ) + 3y × 5( a - b ) - 4z × 2 ( a - b )
= 2x( a - b ) + 15y( a - b ) - 8z ( a - b )
= ( a - b ) ( 2x + 15y - 8z )
I hope this helps you.
: )
misterunknown0065:
Seriously u made it easy.....
Answered by
24
Answer:
(a-b) (2x+15y-8z)
Steb - by- step
2x(a-b)+3y(5a-5b)+4z(2b-2a)
- 2x(a-b)+3y*5(a-b)-4z*2(b-a)
- 2x(a-b)+3y*5(a-b)-4z*2(b-a)2x(a-b)+15(a-b)-8z(a-b)
- 2x(a-b)+3y*5(a-b)-4z*2(b-a)2x(a-b)+15(a-b)-8z(a-b)(a-b) (2x+15y-8z)=answer
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