Question

factorise by using identity 27p^3+q^3

Answer 1

Answer :

Now,

27 p^3 + q^3

= (3 p)^3 + q^3

= (3p + q) { (3 p)^2 - (3 p × q) + q^2 }

= (3p + q) (9 p^2 - 3pq + q^2),

which is the required factorization.

Identity rule :

a^3 + b^3

= (a + b) (a^2 - ab + b^2)

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Answer 2

Hello friends!!

Here is your answer :

$27 {p}^{3} + {q}^{3}$


${(3p)}^{3} + {(q)}^{3}$


Using identity :

a³ + b³ = ( a + b ) ( a² + b² - ab )


$(3p + q)( {(3p)}^{2} + {(q)}^{2} - (3p)(q))$


$(3p + q)(9 {p}^{2} + {q}^{2} - 3pq)$


Hope it helps you.. ☺️☺️☺️☺️

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