Question

Factorise completely:-

a.) 2a⁴– 32 b² c²​

Answer 1

Step-by-step explanation:

2a^4-32b^2c^2

=2(a^4-16b^2c^2)

=2{(a^2)^2-(4bc)^2}

=2{(a^2+4bc)(a^2-4bc)}

Answer 2

Answer:

2a⁴ - 32 b² c²

= 2 ( a⁴ - 16 b²c²)

= 2 {( a²)² - (4bc)²}

= 2×( a ² + 4bc ) ( a² - 4bc)

I'm not sure if it is correct please follow me and thank me.