Factorise completely x^2-y^2-2x+2y
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★ LINEAR REDUCTION ★
x² - y² - 2x + 2y
x + y ( x - y ) - 2x + 2y
x + y ( x - y ) -2 ( x - y )
x - y [ x + y - 2 ]
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
x² - y² - 2x + 2y
x + y ( x - y ) - 2x + 2y
x + y ( x - y ) -2 ( x - y )
x - y [ x + y - 2 ]
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
Lokeshkorampalli:
you did one mistake
100% correct and error free
no
a^2-b^2 = (a+b)(a-b)... not a+b(a-b
it's perfect
no
look at my answer
arrived at the same place , and using bracket functions aren't of much importance here
it is important because it tells that you are multiplying (x+y-2) with both x and -y
use your concepts at best , and reducing the complexity of mathematical generality is the prime issue , so , not such important
Answered by
1
x²-y²-2x+2y
= (x+y)(x-y)-2(x-y)
= (x+y-2)(x-y)
= (x+y)(x-y)-2(x-y)
= (x+y-2)(x-y)
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