Question

Factorise each of the following: 1/9x²y² – 1/16y²z² using identites​

Answer 1

Answer:

using identity-

${a}^{2} - {b}^{2} = (a - b)(a + b)$

1/9x²y² - 1/16 y²z²

$({\frac{1xy}{3} }^{2}) - ({ \frac{1yz}{4} }^{2}) = ( \frac{1xy}{3} - \frac{1yz}{4} )( \frac{1xy}{3} + \frac{1yz}{4} )$

this is your answer

Step-by-step explanation:

I hope it is clear to you

please mark me as brainliest

Answer 2

Step-by-step explanation:

(1÷9x^2y^2)-(1÷16y^2z^2)

{(1÷3xy)^2}-{(1÷4yz)^2}

(xy÷3+yz÷4)(xy÷3-yz÷4) [a^2-b^2=(a+b) (a-b) ]

(x^2y^2÷9) (y^2z^2÷16) {on multiplication}