Question

Factorise each of the following:

27-125a^3-135a+125a^2

-_-

Answer 1

Answer:

Hence, a = 1/5

Step-by-step explanation:

Given,

P(x) = 27 - 125a^2 - 135a + 125a^2

Then,

27 - 125a^2 - 135a + 125a^2 = 0

[ - 125a^2 and + 125a^2 will cancel each other ]

=> 27 - 135a = 0

=> 135 a = 27

=> a = 27/135 = 1/5

Hence, a = 1/5

Answer 2

Answer:

$27 - {125a}^{3} - 135a + {225a}^{2}$

$= {3}^{3} - {5a}^{3} - 45(3 - 5a)$

$= {3}^{3} - {5a}^{3} -( 3 \times 3 \times 5a)(3 - 5a)$

$= {3 - 5a}^{3} = (3 - 5a)(3 - 5a)(3 - 5a)$

here your answer mate✌