factorise each of the following 27 y cube + 125 Z cube
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27z^3 + 125z^3
a^3+b^3= (a+b) (a^2+b^2+a-b)
therefore, a= a= 3y ,b=5z
(3y+5z) (3y^2+5z^2+3y-5z)
hope it helps.....
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