factorise each of the following:
3x+6
5xy+10x
Answers
a) 3x+6
=3(x+2)
b) 5xy+10x
= 5x(y+2)
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Answer: 1. 3(x + 2) 2. 5x(y + 2)
Step-by-step explanation:
So lets start off with bit one:
1. 3x + 6
See, whenever you need to factorise a given expression, the first thing you need to do is to find the HCF.
So lets look at the given expression 3x + 6.
Observe the numerical coefficients 3 and 6.
We see that 3 is the highest common factor of 3 and 6.
Other than that, we see that no number divides the two terms 3x and 6 completely.
So how do we factorise once we know the HCF?
Well, its simple. Just divide the 2 terms by the HCF, 3.
Now, 3x / 3 = x
and 6/3 = 2.
Now, on simplifying, we get x + 2.
But we need to write 3x + 6 in such a way that the answer on both LHS and RHS is the same.
Now, from the above we can conclude that 3 × (x + 2) = 3x + 6.
So we can rewrite it as 3(x + 2) = 3x + 6.
2. 5xy + 10x
Lets figure out the HCF first.
Here we see that 5 divides both 5xy and 10x.
However there's another variable which divides the two terms, that is x.
So our HCF becomes 5 × x = 5x.
Now, lets divide the expression by 5x.
5xy ÷ 5x gives us y.
10x ÷ 5x gives us 2.
So we can conclude that 5 × (y + 2) = 5xy + 10x.
This can be written as 5(y + 2).
Hope it helps....
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