Question

Factorise each of the following.4x^2 - 16y^2 + 8y - 1​

Answer 1

Answer:

$\red{ 4x^{2} - 16y^{2} + 8y - 1} \green {= (6x-1)(1-2x)}$

Step-by-step explanation:

$4x^{2} - 16y^{2} + 8y - 1 \\= 4x^{2} - (16y^{2} - 8y +1)\\= (2x)^{2} - [ (4x)^{2} - 2 \times 2x \times 1 + 1^{2} ] \\= (2x)^{2} - ( 4x - 1)^{2} \\= [2x + (4x-1) ][2x -(4x-1)] \\= ( 2x+4x-1)(2x-4x+1)\\= (6x-1)(-2x+1)\\= (6x-1)(1-2x)$

Therefore.,

$\red{ 4x^{2} - 16y^{2} + 8y - 1} \green {= (6x-1)(1-2x)}$

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Answer 2

Step-by-step explanation:

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