factorise each of the following 8 a cube + b cube + 12 a square b + 6 a b square
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8a^3+b^3+12a^2b+6ab^2
(a+b)^3=a^3+3a^2b+3ab^2+b^3
=(2a)^3+3(2a)^2 (b)+3 (2a)(b)^2+(b)^3
a=2a b=b
(2a+b)^3
(a+b)^3=a^3+3a^2b+3ab^2+b^3
=(2a)^3+3(2a)^2 (b)+3 (2a)(b)^2+(b)^3
a=2a b=b
(2a+b)^3
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