Question

Factorise each of the given : 8a³-b³-12a²b+6ab²

Answer 1

Hey there!

${8a}^{3} - {b}^{3} - 12 {a}^{2} b + 6a {b}^{2} \\ \\ = ( {2a})^{3} + ( { - b})^{3} + 3(2a) ( - b) (2 a - b) \\ \\ = (2a - b) ^{3} \\ \\ = (2a - b)(2a - b)(2a - b)$

$\textsf{formulae} \\ \\ {(a - b)}^{3} = { a}^{3} - {b}^{3} - 3ab(a - b)$

Hope helped!

Answer 2

$<b>$

Using Algebraic Formula :-

[a-b]³= a³-b³-3ab(a-b)


8a³-b³-12a²b+6ab²



= 8a³−b³−12a²b+6ab²




= (2a)³+(−b)³+3(2a)(−b)(2a−b)




=(2a−b)³=(2a−b)(2a−b)(2a−b)