Math, asked by Anonymous, 10 months ago

Factorise following :-​

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Answers

Answered by amayra324
1

Answer:

(x-2z+y) (x-2z-y)

Step-by-step explanation:

on rearranging the term:

x^2 - 4xz + 4z^2 - y

(x)^2 -2 × x ×2z+(2z)^2 -y^2

using identity a^2 -2ab +b^2 =(a - b)^2

(x-2z)^2 -y^2

using identity a^2-b^2=(a+b) (a-b)

(x-2z+y) (x-2z-y)

: .x^2-y^2-4xz+4z^2=(x-2z+y) (x-2z-y)

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