Factorise following quadratic polynomials using factor theorem :-
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Given
Factorise following quadratic polynomials using factor theorem :-
Solution
By factor theorem
splitting middle term
i) 2x² + 7x + 3
=> 2x² + 6x + x + 3
=> 2x(x+3) + 1(x+3)
=> (x+3)(2x+1)
ii) 4x² - 12x + 9
=> 4x² - 6x - 6x + 9
=> 2x(2x-3) - 3(2x - 3)
=> (2x - 3)(2x - 3)
Alternative method
i) 2x² + 7x + 3
p(x) = 2(x²+7/2x+3)
= x² + 7/2x + 3/2
By trail
p(-3) = (-3)²+7/2 × (-3) + 3/2
= 9 - 21/2 + 3/2 = 0
By factor theorem (x+3) is a factor of 2x²+7x +3
By trail
p(-1/2) = (-1/2)² + 7/2(-1/2) +3/2
= 1/4 - 7/4 + 3/4 = 0
By factor theorem (x+1/2) is a factor of 2x²+7x+3
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