Question

Factorise:
(i)12x²-7x+1
(ii) 2x²+7x+3
(iii)6x²+5x—6
(iv)3x²-x-4

Answer 1

Hope this will help you....

Answer 2

Answer:

12x²-7x+1 = (3x - 1)(4x - 1)

2x²+7x+3 = (2x + 1)(x + 3)

6x²+5x—6 = (6x - 1)(x + 6)

3x²-x-4 = (3x - 4)(x + 1)

Step-by-step explanation:

12x²-7x+1

= 12x² - 3x - 4x + 1

= 3x( 4x - 1) -  1(4x - 1)

= (3x - 1)(4x - 1)

12x²-7x+1 = (3x - 1)(4x - 1)

2x²+7x+3

= 2x² + 6x + x + 3

= 2x(x + 3) + 1(x + 3)

= (2x + 1)(x + 3)

2x²+7x+3 = (2x + 1)(x + 3)

6x²+5x—6

= 6x² + 6x - x - 6

= 6x(x + 1) - 1(x + 6)

= (6x - 1)(x + 6)

6x²+5x—6 = (6x - 1)(x + 6)

3x²-x-4

= 3x² + 3x - 4x - 4

= 3x( x + 1) - 4(x + 1)

= (3x - 4)(x + 1)

3x²-x-4 = (3x - 4)(x + 1)