Question

Factorise :(i) 12x2 – 7x+1(iii) 6x2 + 5x – 6(ii) 2x2 + 7x+3(iv) 3x2 – X – 4​

Answer 1

Answer:

HERE IS YOUR ANSWER:

(i)=12x^2-7x+1

$= 12 {x}^{2} - 7x + 1 \\ = 12 {x}^{2} - 4x - 3x + 1 \\ = 4x(3x - 1) - 1(3x - 1) \\ = (3x - 1)(4x - 1)$

(ii)6x^2+5x-6

$= 6 {x}^{2} + 5x - 6 \\ = 6 {x}^{2} + 9x - 4x - 6 \\ = 3x(2x + 3) - 2(2x + 3) \\ = (2x + 3)(3x - 2)$

(iii)2x^2+7x+3

$= 2 {x}^{2} + 7x + 3 \\ = 2 {x}^{2} + 6x + x + 3 \\ = 2x(x + 3)1( x+ 3) \\ = (x + 3)(2x + 1)$

(iv)3x^2-x-4

$= 3 {x}^{2} - x - 4 \\ = 3 {x}^{2} - 4x + 3x - 4 \\ = x(3x - 4)1(3x - 4) \\ = (3x - 4)(x + 1)$

HOPE IT HELPS U............................