Math, asked by parth2271544, 5 months ago

Factorise :
(i) p2-9​

Answers

Answered by kumarvimlesh026
2

(p+3)(p−3)

Step-by-step explanation:

Rewrite 99 as 3232.

p2−32p2-32

Since both terms are perfect squares, factor using the difference of squaresformula, a2−b2=(a+b)(a−b)a2-b2=(a+b)(a-b)where a=pa=p and b=3b=3.

(p+3)(p−3)

Answered by Saifil
1

Answer:

p square - 9

= (p) square - (3) square

=(p-3)(p+3)

Hence,your answer is (p-3)(p+3)

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