Question

factorise (i) p⁴-16 (ii) x²-(y+2z)²​

Answer 1

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$(1) \\ \\ = {(p)}^{4} - 16 \\ \\ = { ({p}^{2}) }^{2} - {(4)}^{2} \\ \\ = ( {p}^{2} + 4)( {p}^{2} - 4)$

$\\ (2) \\ \\ = {x}^{2} - (y + 2z) {}^{2} \\ \\ = {x}^{2} - ( {y}^{2} - 4yz + 4 {z}^{2} ) \\ \\ = {x}^{2} - {y}^{2} + 4yz - 4 {z}^{2}$

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Answer 2

Answer:

Step-by-step explanation: