Question

factorise
(i) y^2-3y-28

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Answer 1

$Given \: Quadratic \: polynomial \:y^{2}-3y-28$

/* Splitting the middle term,we get */

$= y^{2} + 4y - 7y - 28$

$= y(y+4) - 7(y+4)$

$= (y+4)(y-7)$

Therefore.,

$\red{ Factors \: of \:y^{2}-3y-28}$

$\green {= (y+4)(y-7) }$

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