Question

Factorise i) z3 + 27x3 - 9xz2 + 27x2z
The answer should be (x - 3z)2​

Answer 1

Answer:

$z {}^{3} + 27x {}^{3} - 9xz {}^{2} + 27x {}^{2}z \\ \\ (z) {}^{3} +( 3x) {}^{3} - 3(z) {}^{2} (3x) + \\ 3(z)(3x) {}^{2} \\ \\ we \: kown \: the \: identity \: that \\ (x - y) {}^{3} = x {}^{3} + y {}^{3} - 3x {}^{2} y + 3xy {}^{2} \\ \\ therefore \: it \: becomes \\ (z - 3x) {}^{3}$

Step-by-step explanation:

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Answer 2

MAY BE YOUR QUESTION IS

i) z³ + 27x³ + 9xz² + 27x²z

Ans :(x - 3z)³

Step-by-step explanation:

(x + y)³ = x³ + y³ + 3xy² + 3x²y

(Z)³ + (3x)³ + 3*Z*(3x)² + 3*(z)²*3x

We found that

X = z

Y = 3x

So, (x - 3z)³

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