Question

factorise it : 1-(b-c)²

Answer 1

Heya friend,

1-(b-c)^2
= 1- [(b)^2 -2bc + (c)^2]
=1-b^2+2bc-c^2

Hope it Helps...!!!

Answer 2

Answer:

$\underline{\boxed{\boxed{\boxed{\boxed{\bold{\sf{(1+b-c)(1-b+c)}}}}}}}$

Step-by-step explanation:

$1 - (b-c)^2\\\\= 1^2 - (b-c)^2\\\\\text{Using a^2-b^2=(a+b)(a-b) }\\\\(1+(b-c))(1-(b-c))\\\\= (1+b-c)(1-b+c)$