Question

factorise it
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Answer 1

Answer:

This is a case of (a+b+c)^2

It can be written as

(x)^2 +(3y)^2 +(-2z)^2 + 2(x)(3y) + 2(-2z)(3y) + 2(2z)(x)

Since zy and zx are negative and z is present in both hence x

z will be negative that is why minus sign has been given in (-2z)^2 and it works

So factors are (x +3y -2z)^2 Ans