Question

factorise it (x^2+3x)^2-5(x^2+3x)-y(x^2+3x)+5y​

Answer 1

Answer:

(x^2+3x-y)(x^2+3x-5)

Step-by-step explanation:

Let (x^2+3x) be 'a'

(x^2+3x)^2-5(x^2+3x)-y(x^2+3x)+5y

=a^2-5a-ay+5y

=a(a-5)-y(a-5)

=(a-y)(a-5)

Putting value of 'a'

(a-y)(a-5)

=(x^2+3x-y)(x^2+3x-5)