factorise iv) x3 -12x (x - 4) -64
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Answer:
(x-4)(x-4)(x-4)
Step-by-step explanation:
x³ -12x (x - 4) - 64
= x³ - 3(x)(4) (x - 4) - 4³
= (x-4)³ [ ∵ (a-b)³ = a³ - 3ab(a-b) - b³ ]
so, x³ -12x (x - 4) - 64 = (x-4)(x-4)(x-4)
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