Factorise: (l+m)2 - (l-m)2
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Answered by
18
(l+m)^2 - (l-m)^2
Using x^2-y^2=(x+y)(x-y)
=[l+m+l-m][l+m-(l-m)]
=2l[l+m-l+m]
=2l*2m
=4lm
Answered by
33
Solution ●●●●
____________
= [( l + m ) + ( l - m )] [( l + m ) - ( l - m )]
= ( l + m + l - m ) ( l + m - l + m )
= 2l × 2m
= 4 lm
_______________________
I hope it will help you
____________
= [( l + m ) + ( l - m )] [( l + m ) - ( l - m )]
= ( l + m + l - m ) ( l + m - l + m )
= 2l × 2m
= 4 lm
_______________________
I hope it will help you
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