Factorise :(m+2n)2+101(m+2n)+100
Answers
Answered by
118
Put m+2n=x
then we get equation is
x^2+101x+100=0
x^2+100x+x+100=0
x(x+100)+1(x+100)=0
(x+100)(x+1)=0
now put the value of x in above equation
(m+2n+100)(m+2n+1)=0
then we get equation is
x^2+101x+100=0
x^2+100x+x+100=0
x(x+100)+1(x+100)=0
(x+100)(x+1)=0
now put the value of x in above equation
(m+2n+100)(m+2n+1)=0
Answered by
32
"The value of (m + 2n + 1) (m + 2n + 100) = 0
Given:
To find:
Factorise
Solution:
The given equation is
Let assume m + 2n=k ------ (2)
Substitute the equation (2) in (1)
(k)^2 + 101(k) +100=0
k^2 +101k + 100=0
k^2 + 100k + k +100=0
k (k + 100) + 1 (k + 100)=0
(k+1) (k+100)=0 --- (3)
Substitute the value of k in equation (3)
(m+2n+1)(m+2n+100)=0"
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