factorise m(m-3)-n(n-3)
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Yubraj1:
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m (m-3)-n (n-3)
m^2 -3m -n^2 +3n
m^2 -n^2 -3m +3n
BY using identity a^2 -b^2 = (a+b)(a-b)
(m+n)(m-n) -3 (m-n)
(m-n)(m+n-3)
m^2 -3m -n^2 +3n
m^2 -n^2 -3m +3n
BY using identity a^2 -b^2 = (a+b)(a-b)
(m+n)(m-n) -3 (m-n)
(m-n)(m+n-3)
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