Math, asked by ddthedeblinadeb03, 23 days ago

Factorise
m²x-mnp-mnx+ n²p

Answers

Answered by akarshsinha594

3

Answer:

(m-n)(mx-np)

Step-by-step explanation:

$m^{2} x-mnp-mnx+n^{2} p\\m(mx-np)-n(mx-np)\\(m-n)(mx-np)$

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