Question

Factorise : m³- n³ - m( m² - n² ) + n ( m - n )³​

Answer 1

Answer:

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Step-by-step explanation:

(m^3-n^3) - m(m^2-n^2) + n(m-n)^3

= (m-n)(m^2+mn+n^2) - m(m+n)(m-n) + n(m-n)(m-n)(m-n)

= (m-n)[(m^2+mn+n^2) - m(m+n) + n(m-n)(m-n)]

= (m-n)[m^2+mn+n^2 - m^2-mn + n(m^2–2mn+n^2)]

= (m-n)[m^2+mn+n^2 - m^2-mn + m^2 n–2mn^2+n^3]

= (m-n)[n^2+m^2 n-2mn^2+n^3]

= n(m-n)[n + m^2 - 2mn + n^2]

= n(m-n)[n + (m-n)^2]. Answer