Question

factorise m4n-81n5. factorise the sum​

Answer 1

n(m+3n)(m-3n)(m2+9n2)

Step-by-step explanation:

let the given equation m4n-81n5 be written as

=m4n-81n5

=n(m4-81n4)

=n/(m2)2-(9n2)2/

=n(m2-9n2)(m2+9n2)

=n(m-3n)(m+3n)(m2+9n3)

Answer 2

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${m}^{4} n - 81 {n}^{5}$

$= n( {m}^{4} - 81)$

$n(( {m}^{2} )^{2} - {(9)}^{2} )$

$= n( {m}^{2} + 9)( {m}^{2} - 9)$

$= n( {m}^{2} + 9)( {(m)}^{2} - {(3)}^{2} )$

$= n( {m}^{2} + 9)(m + 3)(m - 3)$

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