factorise of polynomial x square - 22 X + 120
Answers
Answered by
93
x^2 -22x + 120
x^2 - 10 x - 12x + 120
x (x-10) -12(x-10)
(x-10)(x-12)
x^2 - 10 x - 12x + 120
x (x-10) -12(x-10)
(x-10)(x-12)
Answered by
28
Hey
Here is your answer,
x^2 - 22x +120 =0
x^2 -10x -12x +120=0
x(x-10)-12(x-10)=0
(x-10) (x-12) =0
x-10=0
x=10
x-12=0
x=12
Hope it helps you!
Here is your answer,
x^2 - 22x +120 =0
x^2 -10x -12x +120=0
x(x-10)-12(x-10)=0
(x-10) (x-12) =0
x-10=0
x=10
x-12=0
x=12
Hope it helps you!
Similar questions