factorise of the folloeing......
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a^4 - (a^2 - 3b )^2
use identity: (a - b )^2 =a^2 + b^2 - 2ab ,in second part of the given question ,as it is ,
a = a^2, b = 3b
=a^4 - { (a^2)^2 + (3b)^2
- 2(a^2 ) (3b)}
=a^4 - a^4 - 9b^2 + 6a^2b
= -9b^2 + 6a^2b
= 6a^2b - 9b^2
= 3b( 2a^2 - 3b)
hope it helps /
use identity: (a - b )^2 =a^2 + b^2 - 2ab ,in second part of the given question ,as it is ,
a = a^2, b = 3b
=a^4 - { (a^2)^2 + (3b)^2
- 2(a^2 ) (3b)}
=a^4 - a^4 - 9b^2 + 6a^2b
= -9b^2 + 6a^2b
= 6a^2b - 9b^2
= 3b( 2a^2 - 3b)
hope it helps /
Tribhawan:
but you explain
i facorise it
see again
plz see again this post
the answer is (3b) (2a2-3b) in answrr sheet
i explained it fully
my answer is also this check post again
i modified it check again
thanks for help me........
okk wc
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