Question

factorise p^10 + p^4 q^6

Answer 1

$\textbf{Answer :}$

Now, p¹⁰ + p⁴ q⁶

= p⁴ (p⁶ + q⁶)

= p⁴ {(p²)³ + (q²)³}

= p⁴ (p² + q²) {(p²)² - p²q² + (q²)²}

= p⁴ (p² + q²) (p⁴ - p²q² + q⁴),

which is the required factorization.

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Answer 2

here is your answer

:-

${p}^{10} + {p}^{4} {q}^{6} \\ {p}^{4} ( {p}^{6} + {q}^{6} ) \\ {p}^{4} \:(( { {p}^{2} )}^{3} + ( { {q}^{2}) }^{3} ) \\ {p}^{4} ( {p}^{2} + {q}^{2} )(( { {p}^{2} )}^{2} + ( { {q}^{2} )}^{2} - {p}^{2} \times {q}^{2} ) \\ {p}^{4} ( {p}^{2} + {q}^{2} )( {p}^{4} + {q}^{4} - {p}^{2} {q}^{2} )$

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