Math, asked by yuvrajmanral123, 9 months ago

factorise: p^2 - 2√2 - 30 by splitting the middle term......

Answers

Answered by faisalfarheen00

Answer:

p²-2√2p-30

==> p²-5√2p+3√2p-30=0

p (p-5√2) + 3√2(p-5√2)=0

(p+3√2) (p-5√2)

p=(-3√2) or p= 5√2

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Answered by abdul9838

$<b> <body \: bgcolor = "skyblue">$

Hey mate here is Answer

Solution

$\bf \pink{ {p}^{2} - 2 \sqrt{2} p - 30 = 0 } \\ \\ \bf \pink{ {p}^{2} - (5 \sqrt{2} - 3 \sqrt{2} )p - 30 = 0 } \\ \\ \bf \pink{ {p}^{2} - 5 \sqrt{2 } p + 3 \sqrt{2} p - 30 = 0} \\ \\ \bf \pink{p(p - 5 \sqrt{2}) + 3 \sqrt{2} (p - 5 \sqrt{2} ) = 0} \\ \\ \bf \pink{(p + 3 \sqrt{2}) \: (p - 5 \sqrt{2} ) = 0} \\ \\ \bf \pink{p = - 3 \sqrt{2} \: and \: p = 5 \sqrt{2} \: \: answer}$

$<marquee \: behavior = alternate = bgcolor = "red">$

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factorise: p^2 - 2√2 - 30 by splitting the middle term......​

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Hey mate here is Answer

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factorise: p^2 - 2√2 - 30 by splitting the middle term......