Question

factorise (p^2 -4p+4 )-81

Answer 1

Answer:

(p2-4p+4)-81

=(p-2)2-(9)2

=(p-2+9)(p-2-9)

=(p+7)(p-11)

Answer 2

Answer:

By factorising the ($P^2$ -4p+4 )-81  is (p – 11) (p -7)

To find:

Factorise ($P^2$ -4p+4 )-81

Solution:

Reduce the given expression in terms of $a^2$ ,

Therefore,

$P^2$ – 4p + 4 can be written as $(p - 2)^2$

81 can be written as $9^2$

Hence ($p^2$ -4p+4 )-81 =$(p - 2)^2 - 9^2$

The above equation is in the form of $a^2 - b^2$ = (a + b) (a – b)

$(p - 2)^2 - 9^2$ = (p – 2 - 9) (p – 2 + 9)

= (p – 11) (p -7)