Question

The value of x + x(x^x) when x = 2 is:​

Answer 1

To find

→ Value of x +x( x^x)

Solution

As given that value of x is 2 ,So putting the value of x in the given equation.

→ x + x( x^x)

→ 2 + 2(2²)

→ 2 + (4 )2

→ 2 +8

→ 10

hope it helps

Answer 2

Answer:

At x = -2 the function changes from decreasing to increasing;

therefore there is a relative minimum at the value x=-2.

At x = 0 the function changes from increasing to decreasing;

therefore there is a relative maximum at the value x=0.

At x = 2 the function changes from decreasing to increasing;

therefore there is a relative minimum at the value x=2.

So the answer is "f(x) has relative minimums at x = -2 or +2

only, choice (D)