Question

Factorise: p^2– 8p + 16​

Answer 1

Answer:

p^2-(4+4) p+16

p^2-4p-4p+16

p(p-4) -4(p-4)

(p-4) (p-4)

p=4, 4

Answer 2

$\huge\mathfrak\purple{Question \: - }$

Factorise :-

• p²- 8p + 16

$\huge\mathfrak\pink{Solution \: - }$

✯ using the algebraic identity

{(a-b)² = a²-2ab+b²} we can easily factorise the given equation, i.e –

$\implies \: {p}^{2} - 8p + 16 \\ \implies (p) {}^{2} - 2(4 \times p) + (4){}^{2} \\ \implies(p - 4) {}^{2}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀

Hence, p²-8p+16 = (p - 4)²