Question

factorise P of X is equals to X square + 2 X + 1​

Answer 1

Answer:

p(x) = $x^{2} + 2x + 1$

     = $x^{2} + x + x + 1$

     = x( x + 1) + 1( x + 1)

      = ( x + 1 )( x + 1 )

Answer 2

Step-by-step explanation:

Given that,

p(x)=x²+2x+1=0

⇒x²+x+x+1=0                              (∵The factors of 1 = 1 & 1)

⇒x(x+1)+(x+1)=0

⇒(x+1)(x+1)=0

case-(1):               |   case-(2):

x+1=0⇒x=-1        |       x+1=0⇒x=-1

           

                      HOPE THIS WOULD BE HELPFUL FOR YOU