Chemistry, asked by bhawnajaitly048, 9 months ago

For a given reaction at 298K
2C.
2A(g)+B(g)--->2C(g)
If ∆U° = -10kJ /mol ∆S° = -45J/K/mol
Then what will be value of ∆Gº for above reaction?
(1) +930 J mol-1 (2) -25890 J mol-1
(3) 2000 J mol-1 (4) 8500 J mol-1

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Answers

Answered by vidhishagawand2002
0

Answer:

Explanation:

∆Gº= ∆H-T∆S°

∆H= ∆U° +∆n R T

= -10000-1 *8.314*298

= - 3477.572 J

∆Gº = - 3477.572 + 298*45

= -25890 J mol-1

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