Question

Factorise p(x)=x^3-ax^2+6x-a divided by (x-a)

Answer 1

Answer:

ok

Step-by-step explanation:

Here, p(x)=x  

3

+ax  

2

+6x−a, and the zero of x−a is a

So, p(a)=a  

3

+a×a  

2

+6×a−a

               =2a  

3

+5a

              So, by the Remainder Theorem, 2a  

3

+5a is the remainder when x  

3

+ax  

2

+6x−a is divided by x−a.