Question

factorise P2-10p+21 ​

Answer 1

$= > {p}^{2} - 3p - 7p + 21$
$= > p(p - 3) - 7(p - 3)$
$= > (p - 7)(p - 3)$
$= > p = 7 \: \: \: or \: \: \: \: p = 3$
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Answer 2

$\huge\boxed{\ \ \huge\boxed{\ \ \huge\boxed{\bold{p^2-10p+21=(p-3)(p-7)}}\ \ }\ \ }$

$p^2-10p+21 \\ \\ p^2-7p-3p+21 \\ \\ p(p-7)-3(p-7) \\ \\ (p-3)(p-7) \\ \\ \\ \therefore\ p=3\ \ ; \ \ p=7$

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