Question

factorise p7-pq6 please answer me

Answer 1

P^7-pq^6
=p(p^6 - q^6)
=p[ (p^3 ) ^2 - (q^3) ^2]
=p(p^3 +q^3) (p^3 - q^3)
=p(p+q) (p^2 - pq +q^2) (p-q) (p^2 +pq+q^2)