factorise p7-pq6 please answer me
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P^7-pq^6
=p(p^6 - q^6)
=p[ (p^3 ) ^2 - (q^3) ^2]
=p(p^3 +q^3) (p^3 - q^3)
=p(p+q) (p^2 - pq +q^2) (p-q) (p^2 +pq+q^2)
=p(p^6 - q^6)
=p[ (p^3 ) ^2 - (q^3) ^2]
=p(p^3 +q^3) (p^3 - q^3)
=p(p+q) (p^2 - pq +q^2) (p-q) (p^2 +pq+q^2)
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