Question

Factorise please
using Identity

25a^2-4b^2+28bc-49c^2


plzz tell

Answer 1

Answer:

(5a + 2b - 7c)(5a - 2b + 7c)

Step-by-step explanation:

Given Equation is 25a² - 4b² + 28bc - 49c²

= (5a)² - (2b)² + 2 * 2b * 7c - (7c)²

= (5a)² - [(2b)² - 2 * 2b * 7c + (7c)²]

= (5a)² - (2b - 7c)²

∴ a² - b² = (a + b)(a - b)

= (5a + 2b - 7c)(5a - 2b + 7c)

∴ Factorization of 25a² - 4b² + 28bc - 49c² = (5a + 2b - 7c)(5a - 2b + 7c).

Hope it helps!

Answer 2

$\: \: \: \: \: 25 {a}^{2} - 4 {b}^{2} + 28bc - 49 {c}^{2} \\ = 25 {a}^{2} - (4 {b}^{2} - 28bc + 49 {c}^{2} ) \\ = 25 {a}^{2} - {(2 {b} - 7 {c} })^{2} \\ = (5a + 2b - 7c)(5a - 2b + 7c)$



Hope this will help you. 

If you like my answer
Please mark it as brainliest 
And 
Be my follower if possible.