Factorise
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a^8 - b^8
rewrite a^8 as (a^4)^2,and also b^8 as (b^4)^2
(a^4)^2 - (b^4)2
= (a^4 + b^4 ) (a^4 - b^4)
= (a^4 + b^4)(a^2 + b^2) (a^2 - b^2)
= (a^4 + b^4) ( a^2 + b^2) (a + b) (a - b) ✌✌✌
❤❤❤hope it's help you ❤❤❤
and
plz mark me as brainliest ✔️✔️✔️
rewrite a^8 as (a^4)^2,and also b^8 as (b^4)^2
(a^4)^2 - (b^4)2
= (a^4 + b^4 ) (a^4 - b^4)
= (a^4 + b^4)(a^2 + b^2) (a^2 - b^2)
= (a^4 + b^4) ( a^2 + b^2) (a + b) (a - b) ✌✌✌
❤❤❤hope it's help you ❤❤❤
and
plz mark me as brainliest ✔️✔️✔️
oh
Be happy
OK bye Di Mujeh Abbi maths ke question solve Karne hai
OK thks
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