Question

factorise. question in the image

Answer 1

$27 {p}^{3} - \frac{1}{216} - \frac{9 {p}^{2} }{2} + \frac{p}{4}$

$= (3p)^{3} - (\frac{1}{6})^{3} - 3 \times (3p)^{2} \times \frac{1}{6} + 3 \times 3p \times ( \frac{1}{6})^{2}$

$= (3p - \frac{1}{6})^{3}$

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