Question

factorise root 2 x square + 3x + root 2​

Answer 1

$\sqrt{2} {x}^{2} + 3x + \sqrt{2} = 0 \\ \sqrt{2}x^{2} + 2x + x + \sqrt{2} = 0 \\ \sqrt{2} x(x + \sqrt{2} ) + 1(x + \sqrt{2} ) = 0 \\ ( \sqrt{2x} + 1)(x + \sqrt{2} ) = 0 \\ x = - \sqrt{2} \: \: \: \: \: \: \: \: \: \: x = - \frac{1}{ \sqrt{2} }$

Answer 2

Answer:

it's is the answer

Step-by-step explanation:

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