Question

factorise
solve Kar do​

Answer 1

$\red{ Factors \: of \: 2y^{3} + y^{2} - 2y - 1 } \\= 2y^{3} - 2y + y^{2} - 1 \\= 2y( y^{2} - 1) + 1(y^{2} - 1 ) \\= (y^{2} - 1)(2y + 1 ) \\= (y^{2} - 1^{2})(2y-1) \\= (y+1)(y-1)(2y-1)$

$\underline { \blue { By \: Algebraic\: Identity :}}$

$\boxed { \pink { a^{2} - b^{2} = ( a + b )( a - b ) }}$

Therefore.,

$\red{ Factors \: of \: 2y^{3} + y^{2} - 2y - 1 } \\\green {= (y+1)(y-1)(2y-1)}$

•••♪